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Added comments for day 2, puzzle b

master
Noëlle Anthony 6 years ago
parent
commit
ae5daed884
1 changed files with 36 additions and 18 deletions
  1. 36
    18
      02b.py

+ 36
- 18
02b.py View File

@@ -9,24 +9,42 @@ def main(lines):
There's an easy but expensive way to do this. I'll start with that
and see if I can refine it later.
"""
for i, line in enumerate(lines):
if i + 1 != len(lines):
for word in lines[(i+1):]:
diffs = 0
idx = 0
for j in range(len(line)):
if line[j] != word[j]:
diffs += 1
idx = j
if diffs == 1:
print("Found a match: {} and {}".format(line, word))
print("Matched value: {}".format("".join([word[:idx],word[(idx+1):]])))
# Testing a new implementation (should be O(n log n))
#
# lines.sort()
# for i, line in enumerate(lines):
# if i + 1 != len(lines):
# word = lines[i+1]
# diffs = 0
# idx = 0
# for j in range(len(line)):
# if line[j] != word[j]:
# diffs += 1
# idx = j
# if diffs == 1:
# print("Found a match: {} and {}".format(line, word))
# print("Matched value: {}".format("".join([word[:idx],word[(idx+1):]])))
# return

# Original implementation kept for reference (O(n^2))
#
for i, line in enumerate(lines): # enumerate gives us an index and the value at that index
if i + 1 != len(lines): # don't overflow the list
for word in lines[(i+1):]: # only check lines further down the list
diffs = 0 # track the number of differences between lines
idx = 0 # track the index of the most recent difference
for j in range(len(line)): # iterate over the length of a word (they're all the same length)
if line[j] != word[j]: # if this character in the first word is different from the same character in the second
diffs += 1 # increment the number of differences by 1
idx = j # set the difference index equal to the current iteration index
if diffs == 1: # if we only found one difference
print("Found a match: {} and {}".format(line, word)) # print the matched words
print("Matched value: {}".format("".join([word[:idx],word[(idx+1):]]))) # print the matching (NOT non-matching) letters
return

if __name__ == "__main__":
lines = []
with open("02in.txt","r") as f:
for line in f:
lines.append(line.strip())
main(lines)
lines = [] # an empty list for the lines in the input file
with open("02in.txt","r") as f: # open the file. "with" means we don't have to close it
for line in f: # iterate over the lines in the input file
lines.append(line.strip()) # strip the newline character, then add it to the list
main(lines) # and pass the list to our main function.

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