See https://twitter.com/deathbybadger/status/1567425842526945280 for details.
Potato is a single-player, one-page RPG where you play as a halfling, farming and harvesting potatoes while the Dark Lord amasses his forces elsewhere in the world.
You have three scores: DESTINY, POTATOES, and ORCS. Each round, you roll d6 to determine which type of event you experience: a day in the garden, a knock at the door, or a darkening of the world.
For the first two, you then roll a second d6 to determine how your scores change; the third event makes it cost more potatoes to get rid of orcs. (At the beginning of the game, you can spend 1 potato to reduce your ORCS score by 1.) If any score reaches 10, the game ends with that score’s ending; if DESTINY and ORCS reach 10 in the same round, ORCS wins, and if DESTINY and POTATOES reach 10 in the same round, you get a multi-win. (ORCS and POTATOES can never reach 10 in the same round.)
When the simulator has simulated the requested number of games, it will report its results: the number and percentage of wins for each score type, and the mean and median number of rounds it took to win a game.
-v, --verbose Print detailed information about each game.
This gets very long; probably don't use it if
you're asking for a large number of games!
-n, --numruns [N] The number of games to simulate. Default: 10000
-m, --multiwin Announce on the console when a game ends in a
multi-win. This can lead to a lot of output.
-i, --instructions Print these instructions.
-a, --alt Use Wanderer's algorithm for determining when
to spend potatoes to reduce orcs. This spends
a potato if ORCS could win this round and
POTATOES could not, OR if ORCS is greater than
one and a 1d10 comes up less than the ORCS
score. It will only spend a potato if there
are enough potatoes to spend.
-p, --potatoper [N] Use the Potato-Per algorithm for determining
when to spend potatoes to reduce orcs. This
spends a potato when the ratio of POTATOES to
ORCS rises above a certain amount, modified by
the POTATOES cost to reduce ORCS by 1. It will
only spend a potato if there are enough
potatoes to spend.
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